SECTION A (25MKS)
- Figure I shows a reading of a micrometer screw gauge when a metallic spherical ball of mass 31.2g is measured in it.
If the micrometer screw gauge had a zero error of -0.01; what is- The diameter of the sphere (2mks)
7.00+0.34+7.34+0.01 = 7.35mm - The density of the ball (2mks)
- The diameter of the sphere (2mks)
- Name one force that may determine the meniscus of liquid in a glass (1mk)
- Adhesive force
- Cohesive force
- A water pipe of diameter 8.8cm is connected to another pipe of diameter 2.2cm. The speed of the water in the smaller pipe is 40m/s. What is the speed, V1 of the water in the larger pipe? (2 mks)
- The figure below shows a volumetric flask fitted with a glass tube filled with coloured water which was heated to a temperature of 800c
- What was observed when the flame was withdrawn and left for some time? (1mk)
- The level of the water first raises and then dropped.
- Explain the observation made in 4(a) (1mk)
- The glass will first contract causing the level to raise, but liquid contract fast than solid hence the levels go down
- What was observed when the flame was withdrawn and left for some time? (1mk)
- The figure below shows a u-tube connected to a gas supply containing liquids L1 and L2 of densities 1.8g/cm3 and 0.8g/cm3 respectively in equilibrium.
Given that h1=8cm and h2=12cm and the atmospheric pressure is 1.02x105pa. Determine the gas pressure. (3mks)
- A cart of mass 35kg is pushed along a horizontal path by a horizontal force of 14N and moves with a constant velocity. The force is then increased to 21N .Determine:
- The resistance to the motion of the cart. (1mk)
- Resistance = 12N
- The acceleration of the cart. (2mks)
- F = ma therefore a=F/m
21-14 = 7N
a = 7/35
=0.2 m/s2
- F = ma therefore a=F/m
- The resistance to the motion of the cart. (1mk)
- State the unit for spring constant. (1mk)
- newton per meter
-
- How does the position of C.O.G affects the stability of a body? (1mk)
- The higher the position centre of gravity, the lower the stability and the lower the position centre of gravity the more the stable the body is.
- The figure below shows a uniform rod AE which is 40cm long .It has a mass of 2kg and pivoted at D. If 2Nis acting at a point E and 30N force is passed through a frictionless pulley, find the value of x acting at end A. (3mks)
-
0.3 + 20 x 0.1 = 30 x 0.2 + 2 x 0.1
0.3x =6.2 - 2.0
x = 14
-
- How does the position of C.O.G affects the stability of a body? (1mk)
- A turntable of radius 16cm is rotating at 960 revolutions per minute .Determine the angular speed of the turntable. (2mks)
ANS: w=2πf
f= 960/60rev/sec=16 rev/s
w= 2 x 16π = 32π rads/s
w = 100.5 rad/s
- Distinguish between solid and liquid states of matter in terms of intermolecular forces. (1mk)
- In solids the molecules are held in position by strong intermolecular forces .While in liquid the molecules are held together by weak intermolecular force hence they are able to move randomly.
- State two environmental hazards that may occur when oil spills over a large surface area of the sea. (2mks)
- Pollution
- Death of aquatic animals and plant
SECTION B: 55MKS
-
- Define mechanical advantage of a machine. (1mk)
- It’s the ratio of the low to the effort applied in machine.
- In an experiment to investigate the performance of a pulley system with a velocity ratio of 5 the following graph was plotted.
From the graph find- The effort when the load is 450N (1mk)
- Effort =115N
- M.A when the load is 450N (2mks)
- M.A = load/effort
= 450/15
- M.A = load/effort
- The efficiency corresponding to the load of 450N (2mks)
- efficiency = M.A/V.R x 100
=3.913/5 x 100
=78.26
- efficiency = M.A/V.R x 100
- The effort when the load is 450N (1mk)
- Otieno uses the system in (b) above to exit a body of mass 50kg.It rises with a velocity of 0.15m/s. Determine the power developed by Otieno. (3mks)
- power = force x speed
= 500 x 0.15
=75 watts
- power = force x speed
- Define mechanical advantage of a machine. (1mk)
-
- State the law of floatation (1mk)
- A floating object /body displaces its own weight in the fluid it floats
- The figure below shows metallic rod of length 10cm and uniform cross section area 4cm2 suspended from a spring balance with 7.5cm of its length immersed in water. The density of metallic rod is 1.5g/cm3 (Take density of water =1.05g/cm3)
Determine- The mass of the rod (2mks)
- volume of the rod = BA x h
V = A x L
=4 x 10 =40 cm3
mass = volume x density
=40 x 1.5 = 60g
- volume of the rod = BA x h
- The up thrust acting on the rod (2mks)
- The reading of the spring balance (2mks)
- The reading of the spring balance when the rod is wholly immersed in water (3mks
- The mass of the rod (2mks)
- The figure below shows a special type of a hydrometer for testing relative density of milk. The range of the readings of the hydrometer is 1.015 - 1.045
- State the purpose of lead shot (1mk)
- To enable the hydrometer float upright
- How would the hydrometer be made more sensitive (1mk)
- Making the stem thinner.
- Indicate appropriately on the diagram the given range of the readings of the hydrometer that correspond to the points marked X and Y. (1mk
- The milk is then mixed with another liquid whose density is higher. State what is observed on the hydrometer. (1mk)
- ANS: The hydrometer will sink less in the liquid mixture
- State the purpose of lead shot (1mk)
- State the law of floatation (1mk)
-
- What is meant by specific latent heat of vaporization of a substance? (1mk)
- It’s the amount of leaf required to change a unit mass of liquid to vapour at a constant temperature.
- In an experiment to determine the specific latent heat of vaporization of water steam at 1000c was passed into water contained in a well lagged copper calorimeter .The following measurements were made.
- Mass of calorimeter = 60g
- Mass of water and calorimeter = 145g
- Final mass of calorimeter +water +condensed steam = 156g
- Final temperature of the mixture = 480c
Take specific heat capacity f water =420Jkg-1k-1
Specific heat capacity of copper=390Jkg-1k-1
Determine the- Mass of condensed steam (1mk)
- Mass of steam =156-145
=11g
- Mass of steam =156-145
- The gained by the calorimeter and water if the initial temperature of the calorimeter and water is 200 (3mks)
- Heat gained by water + heat gained by calorimeter.
= 0.055 x 4200 (48 – 20) + 0.06 x 390 x (48 – 20)
= 10651.2 J
- Heat gained by water + heat gained by calorimeter.
- Given that Lv is the specific latent heat of vaporization of steam, write a simplified expression for the heat given out by steam. (2mks)
- Heat lost by steam = Heat lost by condensing steam + Heat lost by condensed steam
= 0.11 x Lv + 0.11 x 4200 x (100 - 48)
= 0.11Lv + 2402.4
- Heat lost by steam = Heat lost by condensing steam + Heat lost by condensed steam
- Determine the value of Lv above (2mks)
Heat lost by steam + heat lost by condensed water = Heat gained by water + Heat gained by calorimeter.
= 0.11Lv + 2402.4 = 10651.2
Lv = 749890.9091JKg-1 - State the assumption made in the experiment above (1mk)
- There are no heat loses.
- There is no change in mass.
- Mass of condensed steam (1mk)
- What is meant by specific latent heat of vaporization of a substance? (1mk)
-
- The speed of a train hauled by a locomotive varies as shown below as it travels between two stations along a straight horizontal track.
Use the graph to determine- The maximum speed of the train (1mk)
- Max speed =24m/s
- Max speed =24m/s
- The acceleration of the train during the first 2min f the journey(2mks)
- V = u + at
24 = 0 + a x 2
2a = 24
a = 12/60 ms-2
a= 0.2 ms-2
- V = u + at
- Time during which the train is slowing down. (1mk
- 3min or 3 x 60=180s
- The total distance between the two stations (3mks)
- distance = area under the graph
= 1/2 (10+5) x 2 x 60
=10800m
- distance = area under the graph
- The average speed of the train (2mks)
- 10800/10 x 60
=18 m/s
- 10800/10 x 60
- The maximum speed of the train (1mk)
- A string of negligible mass has a bucket tied at the end. The string is 60cm long and the bucket has a mass of 45g. The bucket is swung horizontally making 6 revolutions per second.
Calculate- The angular velocity (2mks)
- w=2πf
=2x22/7 x 6
=37.7 rad/s2
- w=2πf
- The angular acceleration (2mks)
- a = rw2
= 0.6 x 37.72
=853.42 rad/s2
- a = rw2
- The tension on the string. (2mks)
- F = ma
=0.45 x 853
=38.4
- F = ma
- The angular velocity (2mks)
- The speed of a train hauled by a locomotive varies as shown below as it travels between two stations along a straight horizontal track.
-
- The diagram below shows asset up that a student used to investigate pressure law of a gas.
- State the measurements that should be taken in the experiment (2mks)
- Temperature
- Pressure
- Explain how the measurement in (i) above may be used to verify the pressure law. (1mk)
- The air gets heated and its temperature noted with the corresponding values of pressure noted on the gauge
- Several values of temperature (T) and corresponding pressure P are tabulated.
- Graph of P against –T is drawn which straight line is showing that pressure is directly proportional to absolute temp.
- State the measurements that should be taken in the experiment (2mks)
- Name one limitation of the gas laws. (1mk)
- Gases liquefy at high pressure and very low temperatures .Real gases have parties that occupy space hence they could be compressed to the volume.
- Oxygen gas of volume of 2500cm3 at 100c and pressure of 3N/m2 is compressed until its volume is 500cm3 at a pressure of 6N/m2 .Determine the new pressure of the gas after this compression in Kelvin.(2mks)
- The diagram below shows asset up that a student used to investigate pressure law of a gas.
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