Question

The interior angles of an irregular hexagon are 108°, 162° and 90°. The remaining three angles are all equal. Find the value of the largest exterior angles.

Answer 1

(180−108)+(180 −162)+90+(6−3)x =360
             72+18+90+3x=360
                               3x=180
                                x=60
(exterior angles = 72, 18, 90, 60)
largest=90°