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The probability of James, Tyson and David passing an examination are 4/5,3/4 and 2/3 respectively. Find the probability that in one attempt:

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The probability of James, Tyson and David passing an examination are 4/5,3/4 and 2/3 respectively. Find the probability that in one attempt:

  1. only one passes the examination. 
  2. All the three passes the examination. 
  3. Two pass the examination. 
  4. None passes the examination. 
  5. At least one passes the examination. 

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  1. (1/3 x 4/5 x 1/4) + (3/4 x 1/5 x 1/3) + (2/3 x 1/5 x 1/4)
    = 1/15 + 1/20 + 1/30= 3/20
     
  2. 4/5 x 3/4 x 2/3 = 2/5
     
  3. (4/5 x 3/4 x 1/3) + (3/4 x 2/3 x 1/5) + (4/5 x 2/3 x 1/4)
    = 1/5 + 1/10 + 2/15
    =13/20
     
  4. 1/5 x 1/4 x 1/3 = 1/60
     
  5. 1 - 1/60 = 59/60

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