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Two towns A and B are 365km apart. A bus left town A at 8;15a.m and travelled towards town B at 60km/hr. At 9.00a.m a car left town B towards town A at a speed of 100km/hr. The two vehicles met at town c which lies between town A and B.

  1. Find the time of the day the two vehicles met.
  2. Find the distance between towns A and C.
  3. At town C the driver of the car took 1 hour for lunch and followed the bus back to town B. Find how fast must the car move to arrive at town B same time as the bus. 

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  1. Relative speed=60+100=160Km/hr
    Relative distance= 365 − (45/60 × 60)
                            =320km
       320  =   2hrs
       160     +9       
                    11.00a.m
    ALT

    45/60 × 60 = 45km
    ∴  x  =  320−x
       60      100
    100x =19200−60
    160x =19200
         x=120km
    120  =2hrs
     60
    9+2=11.00am
     
  2. 45 + 120=165km
  3. Bus=60 × 1 =60km
    Bus to cover 140km
    Car to cover 200km
    200  = 140
      x        60
    x=200 × 60
             140
    x=85.71km/h

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