Question

An air bubble with a volume of 1 cm³ escapes from the helmet of a diver at a depth of 200 m below the water surface. What will be the volume of the bubble immediately it breaks the surface of water? (Take atmospheric pressure = 10 m of water) 

Answer 1

P₁V₁ = P₂V₂
P₁ = (200 +10)m
V₁ = 1cm³
P₂ = 10m
v₂ = ?
210m x 1cm³ = 10m x V₂
v₂ = 210/10
=21cm³