The figure below shows an electric circuit connected to a battery. If the internal resistance of the battery is 0.2Ω.Determine the electromotive force e.m.f of the battery.
Effective resistance=(10 × 5) +2Ω +0.2Ω (10+5)=5.533ΩI in 10Ω=10v/10Ω =1.0AMTotal current=(2.0 +1.0)A =3.0AE=3.0A × 5.533Ω =16.6V
6.4k questions
9.6k answers
6 comments
590 users