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Make K the subject of the formula and simplify.

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t= 2y+1   
    √2ky+k
t2= (2y x 1)2
        2yk+k
t2(2ky +k)= (2y + 1)2 
2ky + k= (2y + 1)2 
                      t2
k(2y + 1)=(2y+1)2
                      t2
k=2y+1
       t2

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