The figure below shows triangle PQR in which PR = 12 cm, T is a point on PR such that TR = 4cm. line ST is Parallel to QRIf the area of triangle PQR is 336 cm2, find the area of the quadrilateral QRTS.
12-4 = 812/8= 3/2a.s.f = 9/124/9 x 336 = 1491/3Area QRST = 336- 149 1/3 = 186 2/3
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