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The figure below shows triangle PQR in which PR = 12 cm, T is a point on PR such that TR = 4cm. line ST is Parallel to QR
MathF4OPP1Q11
If the area of triangle PQR is 336 cm2, find the area of the quadrilateral QRTS. 

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12-4 = 8
12/83/2
a.s.f = 9/12
4/9 x 336 = 1491/3
Area QRST = 336- 149 1/3 = 186 2/3

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