20cm³ of a solution containing 4g per litre of sodium hydroxide was neutralized by 8.0cm³ of dilute sulphuric acid.Culculate the concentration of sulphuric acid in moles per litre.(Na=23,O=16,H=1).

Answer 1

Molar mass of NaOH = 40
Moles of NaOH per littre = 4/40 = 0.4M 
Moles of NaOH reacted = 
H₂SO_4(aq)+2NaOH_(aq)→Na₂SO_4(aq)+H₂O_(l) 
2moles of NaOH react with 1mole of H₂SO₄
Moles of H2SO4 reacting 
Molarity of the acid =