Question

Study the diagram below and answer the questions that follow:

1. Name Liquids A and B
   • A 
   • B 
2. Solid D can be anhydrous calcium chloride. Suggest another suitable reagent that can be used in place of anhydrous calcium chloride. 
3. State the role of D suggested in (ii) above.
4. write a balanced equation for the reaction in the conical flask . 
5. Explain why solid C collects further away from the heated aluminum metal. 
6. In the combustion tube above 0.675g of aluminum metal reacted completely with 1800cm3 of chlorine gas at room temperature. Determine the molecular formula of solid C given that its relative formula mass is 267. (Al = 27, Cl = 35.5, Molar gas volume at r.t.p. = 24.0 litres) 

Answer 1

1.   
   1. - Concentrated hydrochloric acid
   2. - water
2. Calcium oxide/CaO  
3. to absorb unreacted/excess chlorine
4. 2KMnO_4(S)+ 16HCl _(aq)  → 2KCl _(aq)+ 2MnCl_(aq) + 8H₂O_(l) + 5Cl_2(g)
5. Solid C sublimes hence collects on the cooler place away from heating

6. Elements present	Al	Cl2
   MAss/Volume R.A.M/M.G.V No of moles Mole ratio	0.675 27 0.675/27 = 0.025 0.025/0.025= 1 EF=AlCl3	1800cm3 24000cm3 1800/24000= 0.075  0.075/0.025 = 3

   (AlCl₃)n=267 
   (27 + 35.5 x 3)n = 267
   n = ²⁶⁷/_133.5 = 2
   M.F. = (AlCl₃)₂ = Al₂Cl₆