Question

A hydraulic jack has a piston (large piston) diameter of 0.32m while its plunger (small piston)has a diameter of 0.052m. A force of 500N is exerted on the plunger. Determine the upward force in the large piston.

Answer 1

d= 0.32m
f= ?
f= 500
d= 0.052m
^f1/_A1=^F2/_A2

F2= ^F1/_A1 X A2

=      500      X π X 0.16²
   π X 0.026²  

= 18935 N