Given that cos θ= –0.8070 , find θ for 0≤θ≤720

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asked Aug 2, 2021 in Mathematics Form 2 by anony mous

linear inequalities
trigonometry

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answered Aug 2, 2021 by anony mous

θ = cos−1 (−0.8070)
Acute θ =36.20°
2nd & 3rd quad
θ = 180 − 36.20 = 143.8°
θ = 180 + 36.20 =216.2°
Beyond 360° θ = 143.8 + 360 = 503.8°
θ = 216.2 + 360 = 576.2°

Given that cos θ= –0.8070 , find θ for 0≤θ≤720

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