Question

The figure shows a suspended uniform meter rule in equilibrium when a mass of 50g is hang at the zero mark

Determine the tension T in the string

Answer 1

Clockwise moments = anticlockwise moments
W = ⁴⁰/₁₀₀ × ⁵⁰/₁₀₀₀ × 10 × ¹⁰/₁₀₀
40W = 5
    W =0.125N
Tension in the string = 0.5 + 0.125 = 0.625N