The points A, B and C lie on a straight line. The position vectors of A and C are 2i + 3j + 9k and 5i - 3j + 4k respectively; B divides AC internally in the ratio 2:1 Find the:
Position vector of B
OB= 1/3 2 + 5 3 -39 + 2/3 42/3 + 10/31 -23 -8/3= 4= -1 17/3
Distance of B from the Origin
0B = √42+ (-1)2+ (17/3)2 _________________ √ 1b +1+32.11= √49.11=7.007 square units
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