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Solve for x in 2 +log7(3x-4) =log798

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asked Aug 13, 2021 in Mathematics Form 1 by anonymous

Solve for x in 2 +log₇(3x-4) =log₇98

indices and logarithms

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answered Aug 13, 2021 by anonymous

Log₇2 + log₇ (3x-4) = log₇ 98
49 (x - 4) = 98
3x – 4 = 2
3x = 6
X = 2

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