The figure below shows a circle centre O. Chord AB subtends 30° at the centre. If the area of the minor segment is 5.25cm2, find the radius of the circle.
30 × 22 × r2 = 11 r2360 7 42Area of ∆ = ½r2 sin 30 = ¼r2 11 r2 − ¼r2 =5.254284 × 1 r2 =5.25 × 84 84 r2 = 441r2 = √441 r = 21cm
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