10cm3 of a gaseous hydrocarbon, CxHy required 30cm3 of oxygen for complete combustion. If steam and 20cm3 of Carbon (IV) oxide were produced, what is the value of x in CxHy.
CxHy(g)+O2(g)→CO2(g)+H2O(g) 10cm3 30cm3 20cm3Their volumes to mole ratioCxHy(g)+O2(g)→CO2(g)+H2O(g) 1mole 3moles 2molesCxHy(g)+3O2(g)→2CO2(g)+H2O(g) Then 2 atoms of carbon were present in CxHy and 4 atoms of Hydrogen.C2H4(g)+3O2(g)→2CO2(g)+2H2O(g)Thus x = 2
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