Question

A car tyre is at pressure of 5.0x105 Pa at a temperature of 37℃. While it is running the temperature rises to 75℃. What is the new tyre pressure?(Assume the tyre does not expand)

Answer 1

P α T →P=KT →K=P/T
P1 – 5.0 x 105 Pa
P2 = ?
T1 = 273 + 37 = 300k
T2 = 75 + 273 = 348k
P₁/T₁ = P₂/T₂ 
⁵⁰⁰⁰⁰⁰/₃₀₀= P₂/348 
P2 = ^{(500000 ×348)}/₃₀₀
= 580000
P2 = 5.8 x 105 Pa