Question

A factory uses 100 kg of ammonia each day to produce 160 kg of nitrogen(II) oxide. Calculate the percentage yield of nitrogen(II) oxide.

Answer 1

Moles of NH₃ =100,000 =5882.35
Moles of NO = mole ratio 1:1
Molar mass NH₃ =17       Molar mass N=30✓½
Mass of NO = 5882.35 × 30 =176470.58
%yield of No =  ^160,000/ _176,470  × 100 =  90.667%   
    OR           ^{160 × 17  × 100}/ _{30 x 100}   =90.67%