Question

In a certain x-ray tube, the electrons are accelerated by a pd of 12000V. Assuming all the energy goes to produce x-rays, determine the frequency of the x-rays produced. (Planks constant h = 6.62 ×10^-34 J and charge of an electron, e = 1.6 ×10^-19 C)

Answer 1

Energy of electrons = Qv = eV
= 1.6×10^-19×12000
Energy of x-rays = hf = 6.62×10^-34×f
f = ^{_(1.6×10-19_×12000)}/_{(6.62×10^-34 )} 
= 2.9×10¹⁸Hz