Length, Perimeter and Area
Worked Exercise
- Tracy used a piece of wire m long to support tomato plants in the garden. The wire was cut into pieces of 28cm long. How many complete pieces were obtained?
- 85
- 30
- 20
- 30.10
Working
1 M = 100cm
8½m = ?
8½ x 100 = 850cm
1 piece = 28 cm
? = 850cm
= 850/28
= 30 complete pieces remainder 10cm
- The figure below represents a flower garden
What is the perimeter of the garden?- 25m
- 38.5m
- 11m
- 44m
Working
P = ¼П d + r + r
= ( ¼ x 22/7 x 14) + (7+7)
= 11 + 14
= 25 m
The correct answer is A (25)
- The parallel sides of a trapezium measure 10cm by 18cm respectively. If the distance between the parallel sides is 8cm, what is the area of the trapezium in cm²?
- 224
- 112
- 108
- 84
Working
Area of a trapezium = ½h (a + b)
= ½ x 8 x (10+18)
= ½ x 8 x 28
= 112cm²
- The figure below shows vegetable garden.
What is the perimeter?- 0.526m
- 5.26m
- 52.6m
- 526m
Working
Perimeter of semi-circle
= ½П d(Circumference only)
=½ x 2 x 22/7 x 7
= 22m
To get DC = √ 25 – √ 16
= √ 9
= 3m
Length DE = AB – ED
= 12.8 – 7
= 5.8m
Total length 12.8+ 5 + 3 + 5.8 + 22 + 4
= 52.6 m
The correct answer is (52.6)
- What is the perimeter of the following shape?
- 88cm
- 44cm
- 176cm
- 56cm
Working
P = circumference of a circle of radius 7cm
= 2Π r
= 2 x 22/7 x 7
= (44 cm)
- The figure below shows a right angled triangle LMN in which LM = 7.5cm and LN = 19.5cm
What is the area of the triangle in cm²?- 18
- 67.5
- 27
- 34.5
Working
Apply Pythagoras relation in triangle LMN
LN² = LM² + NM²
Nm² = LN² – LN²
= 19.5² – 7.5²
= 380.25 – 56.25
= 324
NM = √ 324
= 18 cm
Area of triangle LMN
= Base x height
= ½ X 18 X 7.5
= 67.5cm²
The correct answer is B (67.5cm²)
- The area of a right-angled triangle is 84cm². If the height of the triangle is 7cm, what is the length of the longest side?
- 25cm
- 24cm
- 19cm
- 12cm
Working
The Pythagoras relationship states that
H² = b² + h²
But Area = ½bh
84 =½ x b x 7
84 x 2 = 7b
24 = b
H² = 24² + 7²
H² = 576 + 49
H² = 625
H = 25
Therefore the correct answer is 25cm (A)
- What is the surface area of an open cylinder whose radius is 6.3cm and height of 25cm.
- 114.74cm²
- 1239.48cm²
- 3118.50cm²
- 619cm²
Working
Total surface area = Πr2+Πdh
= ( 22/7x 6.3 x 6.3) + 2 x 22/7 x 6.3 x 25
= 124.74 + 990
= 1114.74 cm²
The correct answer is 1114.74 cm² (A)
- A Welder made a door with a design as shown below.
What is its area? (Take Π =22/7 )- 15.12m²
- 12.04m²
- 13.36m²
- 21.28m²
Working
Area of the semi- circle = ½Π r²
= ½ x 22/7 x 1.4 x 1.4
= 3.08m²
Area of the rectangle = L x w
= 3.2 x 2.8
= 8.96 m²
Total area = (3.08 + 8.96 )m²
= 12.04 m²
The correct answer is B (12.04m²)
- The diagram below represents a plot with a diameter of 28 meters.
The plot was fenced by erecting posts 4m apart. How many posts were used ? (Π = 22/7)- 12
- 17
- 18
- 19
Working
Perimeter =½ П d + d
= (½ x 22/7 x 28 + 28)
= 72
No of posts = Perimeter/Interval
=72/4
= 18 posts
The correct answer is C (18)
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