Calculate angle PAQ.
< PAQ = <PAM + <QAM
< PAM = sinθ1 =4.5/10.5=0.4286
Sin -1 (0.4286) = 25.38º
< QAM = <PAM = 25.38º
→<LAP = 25.38x2= 50.76º
Calculate angle PBQ.
<PBQ = < PBM + <QBM
< PBM = sin∝1 =45/84=0.5357
Sin-1 (0.5357) = 32.39º
< PBM = <QBM = 32.39º
<PBQ = 32.390x 2 = 64.78º
Calculate the area of the shaded part.
area of segment = area of a section – area of D
Taking (i)
=
= 48.84 – 42.69 = 6.15cm2
Taking (ii)
=
= 39.89 – 31.92 = 7.97cm2
= (6.15 + 7.97) cm2 = 14.12cm2