Question

The figure 4 below shows an object of mass 0.2kg whirled in vertical circle of radius 0.5m at uniform speed of 5m/s.

Determine the tension of the string at;

1. Position A.
2. Position B.
3. At what point is the string likely to cut. Explain.

Answer 1

1. Position A. 
   • T = MV²/r-mg
     = (0.2 × 5²/0.5)- (0.2 ×10) 
     = 10 – 2 = 8N
2. Position B. 
   • T = MV²/r
     = (^{(0.2 × 25)}/_0.5)
     T = 10N
3. At what point is the string likely to cut. Explain. 
   • At C, because tension is high at 12N
     T = ^_MV2/_r+mg