Question

60cm³ of oxygen diffuses through a porous pot in 50 seconds. How long would it take 60cm³ of oxygen gas diffuses through a porous pot in 50sec.How long would it take 60cm³ of Sulphur (iv) oxide to diffuse through the same pot under the same conditions?

Answer 1

M_(SO)g =32+16×2
           =64
M_O =16 × 2
      =32

         =50 × √2
         =70.7seconds