20cm3 of oxygen diffused through a porous partition in 70s .how long would it take 20cm3. Of sulphur VI oxide to diffuse through the same portion under the same condition.
Mo2 = 2 × 16 =32 Mso3 =(32+16×3) = 80 To2 =70secs Tso3 =?Tso3 = √80 70 √32Tso3 = 70√80 = 70×8.944 =110secs √32 5.657
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