Question

50cm3 of oxygen gas diffused through a porous plug in 80 secs. How long will it take 100cm³ of sulphur (IV) oxide to diffuse through the same plug? (S = 32 0= 16)

Answer 1

If 50cm³ → 80sec
  100cm³→ ?
100×80 =160sec
    50

  160  =  √32
TSO₂    √64
TSO2  = 160 × 8
                  √32
          =226.27417sec