50cm3 of oxygen gas diffused through a porous plug in 80 secs. How long will it take 100cm3 of sulphur (IV) oxide to diffuse through the same plug? (S = 32 0= 16)
If 50cm3 → 80sec 100cm3→ ?100×80 =160sec 50 160 = √32TSO2 √64TSO2 = 160 × 8 √32 =226.27417sec
6.4k questions
9.6k answers
6 comments
590 users