Question

20cm³ of oxygen diffused through a porous partition in 70s .how long would it take 20cm³. Of sulphur VI oxide to diffuse through the same portion under the same condition. 

Answer 1

Mo₂ = 2 × 16 =32         Mso₃ =(32+16×3) = 80 
To₂ =70secs                Tso₃ =?

Tso₃ = √80
 70      √32
Tso₃ = 70√80 = 70×8.944  =110secs
            √32          5.657