Common Logarithms Questions and Answers - Form 2 Topical Mathematics

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Questions

  1. Use mathematical table to evaluate.
    logs q1
  2. Given that y = Bxn. Make n the subject of the formula and simplify your answer
  3. Without using mathematical tables or calculators evaluate: 6log264 + 10log3(243)
  4. Find the value of x that satisfies the equation log (2x – 11) – log 2 =log 3 – log x
  5. Use logarithms to evaluate to 3 significant figures
    logs q5
  6. Use logarithm tables in all your steps to evaluate: 
    logs q6
    leaving your answer to four decimal places
  7. Make L the subject in :
    logs q7
  8. Using logarithm tables solve.
    logs q8
  9. Solve the simultaneous equation:-
    Log (x-1) + 2log y = 2log3
    log x + log y = log 6
  10. Without using logarithms tables or calculator evaluate:-
    4/5log1032 + log1050-3log10
  11. Use logarithms to evaluate:-
    logs q11
     
    and express the answer in standard form
  12. Solve for x given that :- log (3x + 8) – 3log2 = log (x-4)
  13. In this question, show all the steps in your calculations, giving your answer at each stage.
    logs q13
    Use logarithms correct to 4 decimal places to evaluate:
  14. Use logarithms to evaluate correct to 4 s.f
    logs q14
  15. Without using logarithm tables evaluate:
    logs q15
  16. Without using a calculator/mathematical tables, solve: Log8 (x + 5) – log8(x -3) = Log84
  17. Use tables to calculate;(6.572 + 6.57) ÷ (7.922 x 30.08)(Give your answer to 4 decimal places)
  18. If log2 = 0.30103, and log3 = 0.47712, calculate without using tables or calculators the value of log120
  19. Solve for x in the following equation; Log2(3x -4) = 1/3log28x6 – log24
  20. By showing all the steps, use logarithms to evaluate: 
    logs q20
  21. Solve the logarithimic equation: log10(6x – 2) – 1 = log10 (- 3)
  22. In this question, show all the steps in your calculations, giving your answers at each stage. Use logarithms, correct to 4 d.p to evaluate:-
    logs q22
  23. Evaluate using logarithms
    logs q23

Answers

  1.  
    logs ans1
  2. Log y = log B + n log x
    n log x = log y – log B
    n = Log (y/B)/Log x
  3. = 6 log24 + 10 log33
    = 12 log22 + 10 log33
    = 12 + 10
  4. Log (2x - 11)/2 = log 3/x
    (2x – 11) = 3/x
    2x2 _ 11x -6 = 0
    (2x + 1 ) (x – 6) = 0
    x = - ½ or 6
    x = 6
  5.  
    logs ans5
  6.  
    logs ans6
  7. H3 = 3d(L - d)/10L
    3dL - 10H3L= 3d2
    L(3d -10H3)3d2
    L = 3d2/3d - 10H3
  8.  
    logs ans8
  9. Log y2 (x-1) = log 9 y2 (x-1) = 9 ….(1)
    log (xy) log 6 xy = 6 ....2
    from (2) x = 6/y
    substitute in (1) y(6 -1)/y = 9
    6y – y2 = 9
    y2– 6y + 9 = 0
    (y-3)2 = 0
    y = 3
    x = 2
  10. 4/5 log1025 + log1025x2 – log 10
    4log 2 = log1025x2 – 3log2
    2log10 + 2log5
    Log 10 x 100
  11.  
    logs ans11
  12. Log 3x + 8 – log 8 = log (x-4)
    Log (3x + 8)/8 = log (x-4)
    3x + 8 = x -4
    3x + 8 = 8x – 32
    5x = 40
  13.  
    logs ans13
  14.  
    logs ans14
  15. From square roots 12.25 = 3.5
    3.264 x 1.215 x 3.5x√107
    1.088 x 0.4725 x 107
    3264 x 1215 x35
    1088 x 4725
    √27 = 3
  16. Log8(x + 5) – log8(x -3) = Log84
    Log8(x + 5)/x – 3 = log84
    x + 5 = 4
    x – 3
    4x – 12 = x + 5
    3x = 17
    x = 17/3 = 52/3
    Or log8x+5/x-3 = 2/3
    8 2/3 = x + 5/x – 3
    23(2/3) = x + 5/x -3
    22 = x +5/x - 34 = x + 5/x - 3
    4x -12 = x + 5 3x = 17
    x = 17/3 = 52/3
  17.  
    logs ans17
  18. Log 120 = log 4 + log 3 + log 10
    = log22 + log3 + log 10
    = 2log2 + log3 + log 10
    = 2(0.30103) + 0.47712 + 1
    = 2.07918
  19. Log2 (3x – 4) = 1/3 lo28x6 – log24
    Log2 (3x – 4) = log2(23x6) - log24
    Log2 (3x – 4) = log22x2 – log2 4
    Log2 (3x – 4) – log2 2x2/4
    = 3x – 4 = 2x2/4
    2x2 – 12x + 16 = 0
    x2– 6x + 8 = 0
    x – 2x – 4x + 8 = 0
    (x – 2) (x- 4) = 0
    x = 2 or x = 4
  20.  
    logs ans20
  21. Det 2 - -3 = 5
    Area of AIBICI = 5 x 15
    = 75 cm2
  22. Log10(6x-2) – log10 = log10(x-3)
    Log (6x -2)/10 = log (x-3)
    6x - 2/10 = x -3
    6x – 2 = 10x -30
    x = 7
  23. No.                    Log
    0.075262           2.8766 x 2 = 3.7532
    6.652                 0.8230 = 0.8230
    4.9302/3 = 6 + 2.9302/3
    = 2.9767
    Antilog = 9.4776 x 10-2
    = 0.094776(accept 0.09478)

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