Questions
- Find without using a calculator, the value of:
- Solve and write down all the integral values satisfying the inequality.
X – 9 ≤ - 4 < 3x – 4 - Solve the inequality and show the solution on the number line.
3 – 2x <x <2x + 5 - Show on a number line the range of all integral values of x which satisfy the following pair of inequalities
3 – x ≤ 1 – ½ x
-½ (x-5) ≤ 7-x - Solve the inequalities 4x – 3 ≤6x – 1 <3x + 8; hence represent your solution on a number line
- Find all the integral values of x which satisfy the inequalities
2(2-x)< 4x -9 < x + 11 - Find the inequalities that define the unshaded region
- Given that x + y = 8 and x²+ y²=34
Find the value of:-- x²+2xy+y²
- 2xy
- Find the inequalities satisfied by the region labelled R
- The region R is defined by x ≥0, y ≥-2, 2y + x ≤2. By drawing suitable straight line on a sketch, show and label the region R
- Find all the integral values of x which satisfy the inequality
3(1+ x) < 5x – 11 < x + 45 - The vertices of the unshaded region in the figure below are O(0, 0) , B(8, 8) and A (8, 0). Write down the inequalities which satisfy the unshaded region
Answers
- 12 x 0.25 – 12.4 ÷ 0.4 x 3
⅛ of 2.56 + 8.68
3 – 31 x 3
0.32 + 8.68
-90/9
= -10 - x - 9 ≤- 4 <3x – 4
x – 9 ≤- 4
x ≤5
3x – 4 >- 4
3x >0
x = 0
0 >x ≤5
{1, 2, 3, 4, 5} - x > 3 – 2x
x ≤2x + 5/3
3 – 2x < x
-2x < x – 3
-3x < - 3
x < 1
2x + 5 ≥3x
-x ≥ 5
x ≤-5
-5 ≤x < 1 - 3 - x≤ 1 – ½x
3 – 1 ≤ x – ½x
2≤ ½ x
x≥ 4
-x + 5≤ 14 – 2x
2x – x ≤ 14 – 5
x≤ 9
4≤ X ≤ 9 - 4x – 3 ≤6x – 1
-2x ≤2
x ≥-1
6x – 1 <3x + 8
3x <9
x <3
-1 ≤x <3 - 2(2-x ) <4x -9
4 – 2n <4x -9
4 + 9 <4x + 2n = 13 6x
=13/6 < n = 21/6 < n
and 4x – 9 <x + 11
4n –n < 11 + 9
3n < 20
x < 20/3= < 2/3
Integral values 3, 4, 5, 6 - L3 : y ≥ 1
L1: y + x ≥ - 1
L2: y – x - x2 + 2xy + y2 = x2 + xy + xy + y2
= x(x + y) + y(x + y)
= (x + y) (x + y)
∴ (x + y)2 = 8 x 8 = 64 - x2 + 2xy + y2 = 64
(x2 + y2) + 2xy = 64
34 + 2xy = 64
2xy = 30
- x2 + 2xy + y2 = x2 + xy + xy + y2
- Equation of L1
(3.5, 4) (0, 2)
y-2 = 2
x-0 3.5-0
3.5y – 7 = 2x
∴y =4/7x = 2x
Inequality of
y ≤4/7x + 2
Or
7y ≤ 4x + 14
Equation of L2
(0, 3) (4, 2)
y - 2 = 3- 2
x – 4 0 -4
-4(y-2) = x-4
-4y + 8 = x -4
-4y = x -12
inequality y ≥- ¼ x + 3
4y ≥–x + 12
Equation of L3
y - 2 = 2
x – 4 -0.5
-0.5(y-2) = 2(x-4)
-5y + 1 = 2x -8
-5y = 2x - 9
y = -4x + 18
in equality y ≤ -4 x+ 18 - Lines to be drawn x = 0, y = 2
2y + x = 2
x 0 2 y 1 0 - 3(1 + x) < 5x – 11
3 +3 x) < 5x – 11
-2x < - 14
x >7
5x – 11< 45
5x < 56
x < 11.2
Integral values are 8, 9, 10, 11 - y ≤ x
x ≤ 8
y ≤ 0
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