Questions
- Given that A is and A-1 is
Find the value of a and b in the expression:
(3 mks) - Solve for the unknowns given that the following is a singular matrix.
- Given that A = and B = and that C = AB, find C-1
- B is a matrix and C is the matrix
If A is a 2 x 2 matrix and A x B = C. determine the matrix A. - An object of area 20 cm2 undergoes a transformation given by the matrix followed by find the area of the final image
- Find the matrix B such that AB = I and A = Hence find the point of intersection of the lines 3x + 2y = 10 and 3y – 4 = x.
- Given that P = and Q = find the matrix product of PQ. Hence solve the simultaneous eqution below
2x – 3y = 5
- x + 2y = – 3 - Solve for x and y in the following matrix equation using elimination method
- A triangle XYZ , X (-1, -1) , Y (-2, -4) Z (-6 , -9) is reflected in the line X axis followed by a reflection in line X= Y. Find the image of the final image
- Triangle ABC is the image of triangle PQR under a transformation M = where P, Q, R map onto A, B, C respectively.
- Given the points P (5, -1) Q (6, -1) and R(4, - 0.5) draw the triangle ABC on the grid provided.
- Triangle ABC in (a) above is to be enlarged by scale factor 2 with centre at (11, - 6) to map onto A1B1 and C1. Construct and label triangle A1B1 and C1 on the same grid.
- By construction, find the coordinates of the centre and the angle of rotation which can be used to rotate triangle AIBICI onto triangle AIIBIICII whose coordinates are (-3, -2) , (-3, -6) and (-1, -2) respectively.
- Triangle ABC with an area of 15 cm2 is mapped onto triangle AIBICI using matrix M = . Find the area of triangle AIBICI.
- T is a transformation represented by the matrix under T a square whose area is 10cm2 is mapped onto a square of area 110cm2. Find the possible values of X
- Triangle A1B1C1 is the image of ΔABC under a transformation represented by the matrix
M =
If the area of triangle A1B1C1 is 54cm2. Determine the area of triangle ABC - Find the matrix B such that AB = I and A = . Hence find the point of intersection of the lines 3x + 2y = 10 and 3y – 4 = x
Answers
-
- (x-3) – (2x) = 0
x-3-2x = 0
-2x + x – 3 = 0
-x -3 = 0
x=3 -
Determinant = + 65 – 49 = 16 -
- 20x (-3 - -8)
100 area of 1st image.
100 x (4 - -3)
700 area of 2nd image -
-
-
-
-
- Det 2 - -3 = 5
Area of AIBICI = 5 x 15
= 75 cm2 - A.S.F = 110 = 11
10
5X (X) - -6 = 11
5X2 + 6 = 11
5x2 = 5
X2 = 1
X = ±1 - Area of the image = Area of the object x Det.
Det. (∆) = 15 – 18 = -3
54 cm2 = A x -3
54 cm2 = A
3
Area of ∆ ABC = 18 cm2 -
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