QUESTIONS
SECTION A (25 marks)
Answer all the questions in this section in the spaces provided.
- Figure 1 shows two parallel rays from a distant object passing through a convex lens:
- Indicate on the diagram, the position of the principal focus on the lens. (1 mark)
- Deremine the focal length of the lens. (1 mark)
- Indicate on the diagram, the position of the principal focus on the lens. (1 mark)
- State the effect of decreasing the distance between the plates of the parallel plate capacitor on the capacitance. (1 mark)
- Figure 2 shows circular waves originating from the principal focus F of a concave mirror and moving towards the mirror.
Complete the diagram to show the refflected waves. (1 mark) - The force of an electromagnetic wave is 4.0 x 106 Hz. Determine its wavelength. (take speed of light as 3.0 x 108 ms-1) (3 marks)
- Figure 3 shows a nail on which a wire is to be wound to make an electromagnet.
By drawing, show how the wire should be wound around the nail so that end A becomes a north pole and B becones a south pole. (1 mark) - It is observed that when the cap of an uncharged electroscope is irradiated with light of high frequency, the leaf of the electroscope rises. Explain this observation. (3 marks)
- Figure 4 shows the magnetic field pattern around two bar magnets placed side by side.
Indicate on the diagram the poles of each magnet. (1 mark) - Figure 5 shows a graph ofcurrent against voltage for a semiconductor diode.
In the space provided, draw a circuit diagram that may be used to obtain values needed to draw the graph in figure 5. (3 marks) - Radium undergoes radioactive decay by emiting an alpha particle to form a daughter nuclide Q as in the reaction:
Determine the values of:- x (1 mark)
- y (1 mark)
- State two uses of a charged gold leaf electroscope. (2 marks)
- The anode of an x-ray tube becomes hot when the tube is in use. State the reason for this. (1 mark)
- Draw a ray diagram to show how a ray of light may be totally internally reflected two timesin an isosceles right anlgled glass prism. (Assume that the critical angle of glass is 420) (2 marks)
- The current of electrons hitting the screen of a cathode ray oscilloscope is 2.0 x 10-4 A.
Determine the number of electrons that strike the screen each second. (take charge of an electron as 1.6 x 10-19 C)
SECTION B (55 marks)
Answer all the questions in this section in the spaces provided. - Figure 6 shows a simple electric bell circuit.
- Name the parts labelled:
- D (1 mark)
- E (1 mark)
- When the switch is closed, the hammer hits the gong repeatedly. Explain why:
- The hammer hits the gong. (2 marks)
- The hammer hits the gong repeatedly. (3 marks)
- Name the parts labelled:
- An electric bulb is rated 60 W, 240 V. Determine:
- the current that flows through it when it connected to 240 V supply. (3 marks)
- the resistance of the bulb. (3 marks)
- Figure 6 shows a simple electric bell circuit.
- One of the causes of energy loss in a transformer is heating in the coils when current flows. State:
- The reason why the current causes heating. (1 mark)
- How the heating can be minimized. (1 mark)
- The input voltage of a transformer is 240 V and its output is 12 V. When an 80 W bulb is connected across the secondary coil, the current in the primary coil is 0.36 A.
Determine:- The ratio Np/Ns of the transformer, (where Np is the number of turns in the primary coil and Ns is the number of turns in the secondary coil) (3 marks)
- The power input of the transformer. (3 marks)
- The power output of the transformer. (1 mark)
- The efficiency of the transformer. (2 marks)
- One of the causes of energy loss in a transformer is heating in the coils when current flows. State:
- Figure 7 shows resistors R1 and R2 connected in parallel. Their ends are connected to a battery of potential difference V volts.
- In terms of V1,R1 and R2, write an expression for:
- Current I1 through R1. (1 mark)
- Current I2 through R2 . (1 mark)
- Total current I in the circuit. (1 mark)
- Show that the total resistance RT is given by (3 marks)
- In terms of V1,R1 and R2, write an expression for:
- Figure 8 shows a negatively charged rod placed near an uncharged conductor resting on an insulating support.
- Show the charge distribution on the conductor. (2 marks)
- State the effect:
- Of momentarily touching the conductor with a finger while the charged rod is still near the conductor. (1 mark)
- On the charge distribution of withdrawing the negatively charged rod after momentarily touching the conductor. (1 mark)
- In the space provided, sketch a diagram to show how the charge in (ii) (II) above would have been distributed if the conductor was a sphere. (1 mark)
- Figure 7 shows resistors R1 and R2 connected in parallel. Their ends are connected to a battery of potential difference V volts.
- Figure 9 shows two speakers S1 and S2 which produce sound of the same frequency. They are placed equidistant from a line AB and a line PQ. (PQ is perpendicular to line AB)
- A student walking from A to B hears alternating loud and soft sounds. Explain why at some point the sound heard is soft. (2 marks)
- The student now walks along line PQ. State the reason the nature of the sound the student hears. (3 marks)
- Figure 10 shows sound waves in air produced by a vibrating tuning fork. R is an air molecule on the path of the waves.
- Using a line, indicate on the diagram a distance d equal to the wavelength of the wave. (1 mark)
- In the space provided, show with an arrow the direction of motion of the air molecule fr as the waves pass. (1 mark)
- Explain the reason for the answer in (ii). (2 marks)
- Figure 9 shows two speakers S1 and S2 which produce sound of the same frequency. They are placed equidistant from a line AB and a line PQ. (PQ is perpendicular to line AB)
- Figure 11 shows an object placed 10cm infront of a concave mirror whose radius is of curvature is 40 cm.
- On the same figure, draw a diagram to show the position of the image formed. (3 marks)
- Use the ray diagram to determine:
- the image distance. (1 mark)
- the magnification. (3 marks)
- State where the position of the image would be if the object had been placed at the principal focus. (1 mark)
- On the same figure, draw a diagram to show the position of the image formed. (3 marks)
- Draw a ray diagram to show the formation of a partially dark shadow and a totally dark shadow during the eclipse of the sun. (3 marks)
MARKING SCHEME
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- Focal length = 10 cm. √1
-
- The capacitance increases. (1 mark)
- Approximately equally spaced lines √ 1
-
- V = fλ
λ = 3.0 × 108
4 × 106
75 m√ 1
- V = fλ
-
correct winding -
- Electrons arbsorb enough energy and are ejected√ leaving the electroscope positively charged √ the leaf is repelled by the stem. √
-
-
OR equivalent
1 mark for correct bias
1 mark for both ammeter and voltmeter
1 mark for means of varying the p.d. across the diode. -
- 4 + x =226
x = 222√ 1 - 2 + y =88
y = 86√ 1
- 4 + x =226
- -estimate the quantity of charge √1
- test for insulating properties √1
- test for the sign of charge √1
- test for presence of charge √1
(any two correct) - It stops the fast moving electrons √ whose kinetic energy is converted to heat.
-
1 mark for ray incident on hypotenuse
1 mark for showing two internak reflections -
1 mark for either formula
= 2.0 × 10-4 × 1 1 mark for substitution
1.6 × 10-19
= 1.25 × 1015 electrons 1 mark for answer -
-
-
- D - soft iron armature √ 1
- E - contacts √ 1
-
- Soft iron core is magnetised √ and 1 attracts the armature √ the hammer hits 1 the gong.
- Contact is broken √ when armature is 1 attracted by the core. The core then loses magnetism. √ 1 The armature loses magnetism and √ springs back making contact again and the process is repeated.
-
-
- I = P
V
= 60
240
= 0.25A √ 1 - R = V
I
R = 240 × 240 = √ OR 240
60 0.25
= 960 Ω
- I = P
-
-
-
- resistance in the coils. √ 1
- use of thicker copper wires. √ 1
-
- NP = VP
NS VS
=240
12
=20
1 - Power input = 80W
- Efficiency = power output
power input
= 80
86.4
= 92.59% √ 1
- NP = VP
-
-
-
-
- I1 = V
R1 - I2 = V
R2 - Ir = I1 + I2
IT = V + V
R1 R2
- I1 = V
- IT = V
RT
V = V + V
RT R1 R2
divide through by V
1 = 1 + 1 HENCE RT =R1R2
RT R1 R2 R1 + R2
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-
-
-concentration of positive charges at sharp end
+ve & -ve charges in correct position -
- The conductor loses the negative charges to earth. √ 1
- The conductor acquires a net √ positive charge/which redistributes itself.
-
+ve charges uniformly distributed
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-
-
-
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- sound is soft when the waves arrive out of phase; √ 1 such waves undergo destructive interference. 1
- same sound - loud. √ 1
Along PQ the waves undergo 1 constructive intereference as they arrive in phase. √ 1
-
-
-
any correct d -
- As the longitudinal waves pass √ molecule R moves along to either side. 1 For a crest, R moves away from source.
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- image distance = 20 cm ± 2 cm √ 1
- magnification = image distance
object distance
=20
10
= 2 ± 0.2 √ 1 - Infinity. √ 1
- Outer pair of rays √
- Inner pair of rays √
- proper labelling of umbra and penumbra √
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