INSTRUCTIONS TO CANDIDATES
- Answer all questions in Section A.
- In section B answer question 6 (compulsory) and either question 7 or 8.
-
- State two adaptations of the amphibian’s skin to gaseous exchange. (2mks)
- Explain how the human nasal cavity is adapted to gaseous exchange. (3mks)
- Explain why the amoeba does not acquire an elaborate gaseous system. (2mks)
- Name the respiratory disease caused by Bordetella pertussis. (1mk)
- A man experienced non-disjunction during meiosis. If the woman he married had normal gamete formation process.
- Work out the likely phenotypes of their off springs. (4mks)
- State two characteristics of individuals with Down’s syndrome. (2mks)
- Give two advantages of transgenic plants. (2mks)
- The diagram below is a side view of the human male reproductive system.
- Name the parts labelled D and G. (2mks)
D-
G- - How are parts labelled E and H adapted for their functions? (4mks)
- Give the names of two accessory sex glands and state their functions. (2mks)
Accessory gland - ………………………………………………………………………………………………
Function - ………………………………………………………………………………………………………….
Accessory gland - ………………………………………………………………………………………………
Function - ………………………………………………………………………………………………………….
- Name the parts labelled D and G. (2mks)
- The set up in the figure below was used to investigate a certain process in plants. Study it and answer the questions that follow.
- Name the apparatus shown in the set up. (1mk)
- Name the process that was being investigated. (1mk)
- Explain what would happen to the air bubble in the capillary tube if the set up was placed in windy conditions. (2mks)
- Other than wind, state four environmental factors that influence the process that was under investigation. (4mks)
- The diagram below represents a bone found on the lower part of the body.
- Identify the bone. (1mk)
- Identify the parts labelled E and F. (2mks)
- Name and give the functions of the parts labelled A and C. (4mks)
- Name the material composing structure D. (1mk)
- During germination and growth of cereal, dry weight of endosperm, embryo and total dry weight were determined at 2 days intervals and results recorded as shown below.
- Using same axes, draw graphs of dry weight of endosperm, embryo and total dry weight against time. (7mks)
- What was the total dry weight on the 5th day? (1mk)
- Account for the:
- Decrease in dry weight of endosperm from day 0 to 10. (2mks)
- Increase in dry weight of embryo from day 0 to 10th day. (2mks)
- Decrease in total dry weight from day 0 to 8. (1mk)
- Increase in total dry weight after the 8th day. (1mk)
- State two factors within the seed and two outside the seed that causes dormancy.
- Within the seed. (2mks)
- Outside the seed. (2mks)
- What are the characteristics of meristematic cells? (2mks)
- Using same axes, draw graphs of dry weight of endosperm, embryo and total dry weight against time. (7mks)
- How is the mammalian ear adapted to its functions? (20mks)
- Describe how free nitrogen in the air is made available to plants and carnivorous animals and finally circulated back into the atmosphere. (20mks)
MARKING SCHEME
-
- State two adaptations of the amphibian’s skin to gaseous exchange. (2mks)
- Moist to dissolve respiratory gas for faster gaseous exchange.
- Thin lined with a one cell thick epithelium for faster diffusion of respiratory gases
- Highly vascularized for faster / efficient transportation of respiratory gases.
- Explain how the human nasal cavity is adapted to gaseous exchange. (3mks)
- Lined with hair to trap dust particles/ foreign materials/ purify (the incoming) air.
- Has mucus; to moisten/ warm the incoming air.
- Explain why the amoeba does not acquire an elaborate gaseous system. (2mks)
- Has a large surface area to volume ratio; for diffusion (across its cell membrane) is adequate.
- Name the respiratory disease caused by Bordetella pertussis. (1mk)
- Whooping cough
- State two adaptations of the amphibian’s skin to gaseous exchange. (2mks)
- A man experienced non-disjunction during meiosis. If the woman he married had normal gamete formation process;
- Work out the likely phenotypes of their offsprings. (4mks)
- State two characteristics of individuals with down syndrome. (2mks)
- Short body with stubby fingers
- Cardiac malfunctions
- Slit eye appearance
- Reduced resistance to infection
- Thick tongue
- Mentally deficient. (mark first two)
- Give two advantages of transgenic plants. (2mks)
- Fast growth
- (Increased) disease and pest resistance
- Drought tolerance/ resistance
- High/ increased yields
- Work out the likely phenotypes of their offsprings. (4mks)
- The diagram below is a side view of the human male reproductive system.
- Name the parts labelled D and G. (2mks)
- D - Urethra
- G - Scrotum/ Scrotal sac
- How are parts labelled E and H adapted for their functions. (4mks)
- E – Has spongy like tissues that are filled with blood causing an erection.
- H – Long and highly coiled to increase surface area for temporary storage of sperms.
- Give the names of two accessory sex glands and state their functions. (2mks)
- Accessory gland – Cowper’s gland
Function – Secretes alkaline fluid that neutralizes the acidity along the urethra. - Accessory gland – Prostate gland
Function – secretes alkaline fluid that to neutralize the vaginal fluids and activate the sperms. - Accessory gland – Seminal vesicle
Function – Secretes alkaline fluid which contains nutrients for sperms.
- Accessory gland – Cowper’s gland
- Name the parts labelled D and G. (2mks)
- The figure below shows a stem of a plant growing round a tree trunk. Study it and answer the questions that follow.
- Name the apparatus shown in the set up. (1mk)
- Potometer
- Name the process that was being investigated. (1mk)
- Transpiration
- Explain what would happen to the air bubble in the capillary tube if the set up was placed in windy conditions. (2mks)
- More water vapour would be blown away reducing saturation around the stomata increasing the rate of transpiration; leading to faster movement of the air bubble;
- Other than wind, state four environmental factors that influence the process that was under investigation. (4mks)
- Temperature
- Humidity
- Light
- Atmospheric pressure
- Availability of water
(Mark first four)
*(Rej; Wind/ Air)
- Name the apparatus shown in the set up. (1mk)
- The diagram below represents a bone found on the lower part of the body
- Identify the bone. (1mk)
- Pelvic girdle
- Identify the parts labelled E and F. (2mks)
- E – Ischium
- F – Pubis
- Name and give the functions of the parts labelled A and C. (2mks)
- A – Acetabulum – It articulates with the ball of femur to form ball and socket joint.
- C – Obturator foramen- it allows passage of blood vessels, nerves and muscles.
- Name the material composing structure D. (1mk)
- Flexible cartilage
- Identify the bone. (1mk)
- During germination and growth of cereal, dry weight of endosperm, embryo and total dry weight were determined at 2 days intervals and results recorded as shown below.
- Using same axes, draw graphs of dry weight of endosperm, embryo and total dry weight against time. (7mks)
A=1mk
S =1mk
P =3mks
C =1 ½ mks
I = 1 ½ mks - What was the total dry weight on the 5th day? (1mk)
- 38; +/−0.5
- Account for the:
- Decrease in dry weight of endosperm from day 0 to 10. (2mks)
- Stored food is hydrolysed into glucose and translocated to the embryo for respiration to produce energy required for germination.
- Increase in dry weight of embryo from day 0 to 10th day. (2mks)
- New cells are made leading to growth of the embryo.
- Decrease in total dry weight from day 0 to 8. (1mk)
- Rate of respiration is higher than that of synthesis of new materials for growth.
- Increase in total dry weight after the 8th day. (1mk)
- First foliage leaves start photosynthesizing thus food accumulates in the seedling or is used in the formation of the structures of the new seedling.
- Decrease in dry weight of endosperm from day 0 to 10. (2mks)
- State one factor within the seed and two outside the seed that causes dormancy.
- Within the seed. (1mk)
- Presence of abscisic acid
- Presence of germination inhibitors (mark first 1)
- Outside the seed. (2mks)
- Lack of water
- Unfavorable temperature
- Absence of light in some plant varieties.
- Within the seed. (1mk)
- What are the characteristics of meristematic cells? (2mks)
- They have a thin cell wall
- They have a dense cytoplasm
- They have no vacuole
- Using same axes, draw graphs of dry weight of endosperm, embryo and total dry weight against time. (7mks)
- How is the mammalian ear adapted to its functions. (20mks)
- Pinna; is wide/funnel-shaped to collect/gather sound waves; and direct them to the auditory canal into the ear;
- Eardrum/tympanic membrane is thin and light; to convert sound waves into vibrations;
- Ear ossicles/maleus, incus and stapes are of high density; to magnify/amplify sound waves;
- Oval window is smaller than eardrum; to magnify the sound waves; and direct them to the inner ear;
- Cochlea is long and coiled; to increase surface area; for attachment of receptor cells/sensory hairs; cochlea has many sensory hairs; which receive sound vibrations and generate impulses;
- Liquid or fluid/endolymph in cochlea; transmit sound vibrations; auditory nerve; transmit impulses to the brain for interpretation; Eustachian tube; link the mouth and middle ear to equalise pressure; between middle and outer ear to prevent damage to delicate eardrum;
- Round window; lose excess vibrations; to avoid continuous stimulation;
- Semi-circular canals; contain receptors for body balance and posture; External auditory canal cells produce/secrete wax; to trap dust particles/solid/micro-organisms that can damage eardrum; Max. 20 mks
- Describe how free nitrogen in the air is made available to plants and carnivorous animals and finally circulated back into the atmosphere. (20mks)
- This is the cycling of nitrogen and its compounds in nature; plants absorb nitrogen in form of nitrates and then assimilate it into plant proteins; animals obtain this nitrogen in plant proteins through feeding on plants; when the animals die and decompose, they release the nitrogen in form of ammonia to the soil; free atmospheric nitrogen is converted into nitrates through a process known as nitrogen fixation; the process occurs in two ways: biological and non-biological; biological fixation of nitrogen is done by nitrogen-fixing bacteria; which are either free-living or symbiotic; symbiotic bacteria are of the genus Rhizobium; and are found in root nodules of legumes (such as pea, clover and alfalfa); the bacteria convert atmospheric nitrogen into ammonia; that is used directly by the leguminous plants to form nitrogen containing organic compounds (amino acids, nucleic acids, proteins); when plants die, the nodules release ammonium compounds into the soil; which are then converted to nitrites; by nitrifying bacteria of genus Nitrosomonas and Nitrococcus (nitrite bacteria) and then to nitrates by Nitrobacter (nitrate) bacteria; free-living micro-organisms that fix nitrogen include putrefying/saprophytic bacteria; (such as Azobacterspp, Clostridium and some algae such as Anabaena, Chlorella and Nostoc); the organisms fix nitrogen into ammonia by break down of protein material in dead organisms; the ammonia is converted to nitrites; then to nitrates; However, denitrifying bacteria (e.g. Pseudomonas denitrificans and Thiobacillus denitrificans); break down/reduce nitrates to nitrites, ammonium compounds and even gaseous nitrogen; a process known as denitrification; the process helps to release free nitrogen into the air for recycling; non-biological nitrogen fixing is carried out by lightning during thunderstorms; the lightning energy, causes atmospheric nitrogen and oxygen to combine forming oxides of nitrogen; which dissolve in rain water to form nitrous acid/nitric acid; that is washed down into the soil; the nitric acid formed reacts with other chemical compounds dissolved in soil water; to form nitrates; the nitrates are then utilized by plants; Max. 20 mks
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