Questions
- The figure below represents a triangular plot ABC. The lengths of AB = 50m, AC = 80m and angle BAC =30o
- Find the length of BC to 2 s.f
- Find the area of the plot in hectares
- The plot is fenced using 4 strands of barbed wire. The length of one roll of barbed wire is 600m and it costs shs.4000. Calculate;
- The length of fencing wire required
- The number of complete rolls to be bought
- The cost of the rolls
Answers
- BC2 = 502 + 802 – 2 x 50 x 80 cos30
= 2500 + 6400 – 6928.20 = 1971.8
∴ BC =√1971.8
= 44.40m
= 44m - Area of the plot
= ½ x 50 x 80 x sin30 = 1000m2
= 1000/10000 ha
= 0.01ha - Length of wire required
= (50 + 80 + 44) x 4 = 696m - Complete rolls to be bought = 2
- Cost (2 x 4000) = Shs.8000
- Length of wire required
- BC2 = 502 + 802 – 2 x 50 x 80 cos30
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