Questions
- Find the area of a regular polygon of length 10 cm and side n, given that the sum of interior angles of n : n –1 is in the ratio 4 : 3
- Calculate the area of the quadrilateral ABCD shown:-
Answers
- 180( n – 2) = 4
180 (n -1 – 2) 3
540n – 1080 = 720n – 2160
720n – 540n – 2160 – 1080
180n = 1080
n = 6
Area of hexagon = 6 (½ x 10 x sin 60)
= 6 x 43.30 = 259.81 cm2 -
Area ∠rt Δ = ½ x 8 x 6
S = (12 + 14 + 10)/2
A = √[18(18-12) (18-14) (18-10)]
= √(18 x6 x 4 x 8)
= √3456
= 58. 79
Total area = 24 + 58.79 = 82.79
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