- Introduction
- Right Angled Triangle Trigonometry
- Sine and Cosines of Complementary Angles
- Trigonometric Ratios of Special Angles: 300, 450, 600.
- Past KCSE Questions on the Topic.
Introduction
Tangent of Acute Angle
The constant ratio between the vertical distance/horizontal distance is called the tangent. It’s abbreviated as tan
Tan∅ = opposite side
adjacent side
Sine of an Angle
The ratio of the side of angle x to the hypotenuse side is called the sine.
Sin∅ = opposite side
hypotenuse
Cosine of an Angle
The ratio of the side adjacent to the angle and hypotenuse.
Cosine∅ = Adjacent
hypotenuse
Right Angled Triangle Trigonometry
Example
In the figure above adjacent length is 4 cm and Angle x= 360. Calculate the opposite length.
Solution
tan 360 = opposite length = PR
adjacent lengh 4
4tan 360 = PR
Therefore PR = 4 x 0.7265 = 2.9060 cm.
Example
In the above O = 5 cm A = 12 cm calculate angle sin x and cosine x.
Solution
sin x = opp O = 5
hyp H H
But H2 = 122×52
= 169
= √169
H = 13
Therefore sin x= 5/13
= 0.3846
Cos x = adj
hyp
=12/13
=0.9231
Sine and Cosines of Complementary Angles
For any two complementary angles x and y, sin x = cos y; cos x = sin y e.g. sin600 = cos 300, Sin300 = cos 600, sin700 = cos 200,
Example
Find acute angles α and β if Sin α = cos 330
Solution
sin α = cos 33
Therefore α + 33 = 90
α = 570
Trigonometric Ratios of Special Angles: 300, 450, 600.
These trigonometric ratios can be deducted by the use of isosceles right – angled triangle and equilateral triangles as follows.
Tangent, Cosine and Sine of 45o.
The triangle should have a base and a height of one unit each, giving hypotenuse of √2.
Cos 45o = 1/√2
Sin 45o= 1/√2
Tan 45o = 1
Tangent, Cosine and Sine of 30o and 60o.
The equilateral triangle has a sides of 2 units each
Sin 300 = 1/2
Cos 300 = √3/2
Tan 300 = 1/√3
Sin 600 =√3/2
Cos 600 = 1/2
Tan 600= √3/1 = √3
Past KCSE Questions on the Topic.
- Given sin (90 − a) = ½ , find without using trigonometric tables the value of cos a (2mks)
- If θ = 24/25, find without using tables or calculator, the value of
tan θ − cos θ
cos θ + sin θ - At point A, David observed the top of a tall building at an angle of 30o. After walking for 100meters towards the foot of the building he stopped at point B where he observed it again at an angle of 60o. Find the height of the building
- Find the value of θ, given that ½ sinθ= 0.35 for 0o ≤ θ ≤ 360o
- A man walks from point A towards the foot of a tall building 240 m away. After covering 180m, he observes that the angle of elevation of the top of the building is 45o. Determine the angle of elevation of the top of the building from A
- Solve for x in 2Cos 2x0 = 0.6000; 00≤ x ≤ 3600.
- Wangechi whose eye level is 1 82cm tall observed the angle of elevation to the top of her house to be 32º from her eye level at point A. she walks 20m towards the house on a straight line to a point B at which point she observes the angle of elevation to the top of the building to the 40º. Calculate, correct to 2 decimal places the ;
- distance of A from the house
- The height of the house
- Given that cos A = 5/13 and angle A is acute, find the value of:-
2 tan A + 3 sin A - Given that tan 5° = 3 + √5, without using tables or a calculator, determine tan 25°, leaving your answer in the form a + b√c
- Given that tan x = 5/12, find the value of the following without using mathematical tables or calculator:
- Cos x
- Sin2(90−x)
- If tan θ =8/15, find the value of Sinθ − Cosθ without using a calculator or table
Cosθ + Sinθ
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