INSTRUCTIONS TO CANDIDATES
- Answer ALL the questions in the spaces provided.
- You are not allowed to start working with the apparatus for the first 15 minutes of the 2¼ hours allowed time for the paper.
- Use the 15 minutes to read through the question paper and note the chemicals you require
- Mathematical tables and electronic calculators may be used.
- All working MUST be clearly shown where necessary.
- Solution A is prepared by dissolving 6.3g of the organic acid H2C2O4.nH2O in water to make a litre of the solution.
Solution B: 0.1M NaOH solution
Phenolphthalein indicator
Clamp and stand
Burette and pipette.
You are required to determine the value of n in the organic acid H2C2O4. nH2O
Procedure.
Fill the burette with solution A and adjust the volume to zero mark.
Add 2 to 3 drops of phenolphthalein indicator and titrate solution A against solution B until thecolour just permanently changes. Record your results in the table below. Repeat the procedure two more times to obtain concordant results.
Titration 1 2 3 Final burette reading (cm3) Initial burette reading (cm3) Volume of solution A used (cm3) - Calculate the average volume of solution A used. 1mark
- Calculate the moles of sodium hydroxide in the volume of solution B used. 2marks
- Given that solution B - Sodium hydroxide and solution A organic acid react in the ration of 2:1, calculate the number of moles of the organic acid –solution A used? 2marks
- Calculate the moles of organic acid solution A used per litre of solution 2marks
- Calculate the relative formula masses of the organic acid solution A 3marks
- Calculate the value of n in H2C2O4.nH2O(H=1, C=12, O=16) 3marks
- You are provided with CBI. Carry out the test below. Write your observation and inferences in the spaces provided.
- Using a clean spatula, heat about one third of the solid CBI in a non- luminous Bunsen burner flame.
Observation Inferences (1mk) (1mk) - Put a half spatula endful of CBI in a test tube. Heat gently and then strongly. Test for any gas produced using litmus papers.
Observation Inferences (1mk) (1mk) - Put 2cm3 of dilute hydrochloric acid into a test tube. Add ¼ endful of CBI into the test tube.
Test for any gas procedure.
Observation Inferences (2mks) (2mks)
- Using a clean spatula, heat about one third of the solid CBI in a non- luminous Bunsen burner flame.
- You are provided with solid Q, carry out the test below. Record your observations and inferences in the table. Identify any gas (es) evolved.
Place all the solid Q provided into boiling tube and add distilled water until the tube is ¼ full. Divide it into five portions.- To the 1st portion add ammonia solution drop wise until excess.
Observation Inferences 1mk) (1mk) -
- To the 2nd portion add sodium hydroxide solution dropwise until in excess. Keep the resulting mixture for the next test.
Observation Inferences (1mk) (1mk) - Warm the preserved mixture from b (i) above
Observation Inferences (1mk) (1mk)
- To the 2nd portion add sodium hydroxide solution dropwise until in excess. Keep the resulting mixture for the next test.
-
- To the 3rd portion add silver nitrate solution. Preserve the mixture for the next test.
Observation Inferences (1mk) (1mk) - To the preserved mixture in c (i) above add diluted nitric acid.
Observation Inferences (1mk) (1mk)
- To the 3rd portion add silver nitrate solution. Preserve the mixture for the next test.
- To the 4th portion add dilute Barium nitrate solution followed by dilute nitric acid.
Observation Inferences (1mk) (1mk) - To the 5th portion add 2-3 drops of conc. Nitric acid.
Warm the mixture and allow to cool. Add sodium hydroxide solution dropwise until in excess.
Observation Inferences (2mks) (1mk)
- To the 1st portion add ammonia solution drop wise until excess.
CONFIDENTIAL
Per Student
- Solution A (100ml)
- Solution B (100ml)
- Phenolphthalein indicator
- 3 conical flasks
- Funnel
- Burette
- Pipette
- Clamp
- Stand
- CBI(g) – NaHCO3(s)
- Clean spatula
- Test- tubes (5)
- Litmus papers ( 2 blue and 2 red)
- Distilled water
- Solid Q – 1g (NH4)2 SO4.FeSO4. 6H2O and NaCl (ration 1:1)
- 1 boiling tube
Access to; - 2M ammonia solution
- 2M Sodium hydroxide solution
- Source of heat
- Silver nitrate solution (0.05M)
- Dilute nitric acid (0.1M)
- Dilute hydrochloric acid (0.1M)
- Dilute Barium nitrate solution (0.1M)
- Conc. Nitric acid in dropper bottles
- White tile
- Test tube holder
- Solution A is prepared by dissolving 6.3g of H2C2O4. 2H2O in 400cm3 of water and topped upto one litre of solution.
- Solution B is prepared by dissolving 4g of Sodium hydroxide in 400cm3 of water and topped upto one litre of solution.
MARKING SCHEME
Question one
-
- Complete table √1mk
Complete table with 3 titres √1mk
Incomplete table with 2 titres √½ mk
Incomplete table with 1 titre −0 mk
Conditions
✔ Penalize ½ mk for unrealistic values unless where explained
✔ Penalize ½ mk for any inversion of table
✔ Penalize ½ mk for any arithmetic error
NB: penalize a maximum of ½ mk for any of the conditions above. - Decimal √1mk
Award 1mk for 1d.p. or 2 d.p used consistently
If 2d.p used, 2ndd.p. can only be “0” or “5” - Accuracy √1mk
Award 1mk for any value + 0.1 of s.v.
Award ½ mk for any value + 0.2 of s.v.
Award 0mk (penalize fully) for any value beyond + 0.2 of s.v. - Principles of averaging √1mk
Values averaged must be consistent
If 3 titres but only 2 are consistent and averaged award 1mk
If 3 titres done and averaged award 1mk
If 3 titres done and inconsistent and averaged award 0mk
If 3 titres done and all are consistent but only 2 are averaged award 0mk - Final answer √1mk
Award 1mk for ans. + 0.1 of s.v.
Award ½mk for ans. + 0.2 of s.v.
Award 0mk if ans not within + 0.2 of s.v.
Marks awarder as follows:
- CT 1mk
- D 1mk
- A 1mk
- PA 1mk
- FA 1mk
5mks
- Complete table √1mk
- Average titre = t1 + t2 + t3 = (√½ mk)Correct Ans ½ mk
3 - Moles of NAOH = M x V
1000
= 0.1 x 25 √1mk = 0.0025moles √1mk
1000 - 2 NaOH(aq) + H2C2O4(aq) → Na2C2O4(aq) + 2H2O(l)
Moles ratio = 2 :1
Therefore moles of organic acid = ½ x 0.0025 moles √1mk
= 0.00125 moles √1mk - Ans (b) cm3 has → 0.00125moles
1000cm3 → ?
= 0.00125 x 1000 √1mk
Ans (b)
= ______ Correct answer √1mk - Ans (e) moles / L → has 6.3g/l
1mole → ? √1mk
= 6.3 x 1 √1mk
Ans (e)
= _______ Correct answer √1mk - Value of n
Ans (f) = H2C2O4. nH2O
Ans (f) = 2 + 24 + 64 + 18n √1mk
N = ans f – 90 √1mk
18
= _______ correct ans √1mk
Question two
Observation | Inferences | |
(a) | Yellow flame √1mk | Na+ ions √1mk |
(b) |
|
Gas acidic CO32- , HCO3- ions Hydrated salt / water of crystallization Any 2 correct x ½ = √1mk |
(c) |
|
CO32- , HCO3- ions Gas acidic Any 2 x 1 = √2mks |
Question three
Observation | Inferences | |
(a) | Pale green ppt√½ mk insoluble in excess √½ mk |
Fe2+√1mk |
(b) (i) |
Pale green ppt√½ mk |
Fe2+√1mk |
(ii) |
|
Gas basic √½ mk NH4+ ions present√½ mk |
(c) (i) | White ppt | CO32-, Cl-ions , SO32- |
(ii) | White ppt√½ mk Insoluble / persists √½ mk |
Cl- ions √1mk Confirmed |
(d) | White ppt√½ mk Insoluble √½ mk |
SO42- ions √1mk |
(e) | Pale green solution turns to yellow solution √1mk Brown ppt insoluble in excess √1mk |
Fe2+ oxidized to Fe3+ ions √½ mk Fe3+ ions confirmed √½ mk |
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