INSTRUCTIONS:
- You are supposed to spend the first 15 minutes of the 2□(1/2) hours allowed for this paper reading the whole paper carefully before commencing your work.
- Marks are given for a clear record of the observations made, their suitability, accuracy and use.Candidates are advised to record their observations as soon as they are made.
- Candidates should answer the questions in English.
QUESTIONS
Question 1.
You are provided with the following apparatus
- One boiling tube.
- One 100ml measuring cylinder.
- A piece of string 100cm long.
- A half metre rule.
- One retort stand.
- One boss and a clamp.
- A marble.
- Water source.
- Weighing balance
Procedure.
- Weigh and record the mass mo of the marble.
mο =………………g (1/2 mark) - Clamp the boiling tube vertically with its base resting on the bench. Pour 5cm3 of water from the measuring cylinder into the boiling tube.
- Using the half meter rule, measure the height, h, of the water column in the boiling tube and record in table 1 below.
- Repeat the experiment with values of V = 10, 15, 20, 25, 30, 35, 40, 45 and 50cm3 and complete the table below. (5mks)
- Clamp the boiling tube vertically with its base resting on the bench. Pour 5cm3 of water from the measuring cylinder into the boiling tube.
- Plot a graph of volume V against height h of water column (5mks)
- Determine the slope of the graph and state its units. (3mks)
- Measure the length of the boiling tube H
H = ……………………cm (1/2 mark) - Wrap the cotton thread round the boiling tube ten times. Measure the length L of the thread. (Ensure that the windings are very close together)
L……………………………….m (1mk) - Calculate the volume Vb of the glass material of the boiling tube using the formula
Vb = H (2L2 – 5/2500) (2mks) - Empty the boiling tube and pour 50cm3 of water from the measuring cylinder. Measure and record the height h1 .
h1= ………………………………..cm (1/2 mark) - Carefully slide the marble into the boiling tube and record the new height h2
h2 = ……………………………….cm (1/2 mark) - From the graph determine the volume V1 and V2 corresponding to h1 and h2 hence determine the density ℓ of the material of the marble given that
(2marks)
- Plot a graph of volume V against height h of water column (5mks)
QUESTION TWO.
- You are provided with the following apparatus.
- convex lens
- Candle
- White screen
- Lens holder
- Meter rule.
- Procedure
- Set up the apparatus as shown in figure below.
- Place the lit candle at an object distance U=30cm. Move the screen towards or away from the lens until a sharp image of the candle flame is obtained on the screen.
- Measure the distance V and record it in table 2.
- Repeat the experiment for other values of U and record in the table.
- Complete the table. (6 marks)
- Determine the average value of f. (2marks)
- Determine the power of the lens used in the experiment. (2 marks)
- Set up the apparatus as shown in figure below.
- You are provided with the following apparatus
- A New dry cell
- An ammeter
- A voltmeter
- A mounted wire labeled AB
- Cell holder
- Switch
- Connecting wires
You are required to design a circuit that you will use the above apparatus to determine the resistance of the wire AB.- Draw the circuit diagram (2mks)
- Connect the circuit you have drawn and record the measurement required. (2mks)
- Showing the workings to determine the resistance of the wire. (2mks)
- You are further provided with a meter rule and a micrometer screw gauge,
- Measure the diameter of the wire. (1/2 mk)
- Measure the length of the wire. ( 1/2 mk)
- Determine the cross sectional area of the wire. (1mk)
- Determine the resistivity of the material of the wire. (2marks)
MARKING SCHEME
QUESTION I
- Mass = ±5.4g
- Graph
- Axis ,both labelled or with correct units-1mk
- Scale, simple and uniform -1mk
- Plotting, all points correctly plotted- 2mk
- line, pass through at least 6 correctly plotted points -1mk
- Slope = 25 – 10/6.6 – 3
= 4.1667cm2 - H = 15.0 cm, ±0.2cm, 1d.p
- L = 86.5cm ±1.0cm, 1d.p
- V = 15(2 x 0.8152 – 5/2500)
= 22.42cm3, - h1 = 12.5cm ±0.5cm, 1d.p
- h2 = 13.0cm ±0.5cm, 1d.p
- V1 = 49cm3 V2 = 51cm3
5.4/51 – 49
= 2.7g/cm3
- Graph
QUESTION 2
- use students values for the average
- Principle of averaging- 1 mark
- Correct evaluation to 4sf or exact with units-1mark
- power of lens=1/f (m)
=1/ value in (d) above units Dioptres, D
2 (ii) (a)
b) A graph V against I is drawn
V= 3.0V
I= 0.3A
(c) R=v/I
(d) (i) Diameter = 0.28mm±0.2mm,2d.p
(ii) Length 60.0cm±2.0cm, 1d.p
(iii) calculation of area in m2
(iv) ρ=RA/L
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