- This paper consists of three questions
- Answer all the questions in the spaces provided.
- You are required to spend the first 15 minutes of the 13/4 Hours allowed for this paper reading through all the questions before commencing your work.
For Examiners Use Only
Question |
Maximum score |
Candidate’s score |
1 |
16 |
|
2 |
11 |
|
3 |
13 |
|
Total Score |
40. |
|
QUESTIONS
- You are provided with a suspension labelled M.
- Using the reagents provided only, test for the food substances present in the suspension. In the table below, record the food tested, procedure, observation and conclusions. 12 marks.
Food TEST
Procedure
Observation
Conclusion
- Name two enzymes that may be required to digest suspension M in the alimentary canal in human. (2mark)
- State role of the following in the experiment. (2marks)
- sodium hydrogen carbonate
- Dilute hydrochloric acid
- Using the reagents provided only, test for the food substances present in the suspension. In the table below, record the food tested, procedure, observation and conclusions. 12 marks.
- Experimental evidence shows that most mutations results to variations among organisms. The illustrations I, II, III and IV below show different possible types of chromosome mutations. Study them keenly.
- Identify the types of chromosome mutations illustrated.(4 marks)
Illustration Name of mutation
I
II
III
IV - State the effect of the mutation illustrated in III. (1 mark)
- In most cases, the mutation in II could be lethal. Explain. (2 marks)
- During which stage of mitosis does the mutation in I above occur? (1 mark)
-
- Define a mutation (1 mark)
- Give two possible environmental mutagens. (2marks)
- Identify the types of chromosome mutations illustrated.(4 marks)
- The diagrams below represent body parts of some organisms (animals). Study them and answer the question that follow
-
- Suggest the type of food eaten by organisms with the parts labeled A, B, C and F
Food Reason
A
B
C
F (4mks) - With reasons, suggest the likely habitat of the organism from which the parts labeled D and E were obtained
Part Habitat Reason
D
E (4mks)
- Suggest the type of food eaten by organisms with the parts labeled A, B, C and F
-
- Suggest the type of evolution that is exemplified by the organisms labeled D, E and F. Give reason for your answer
The type of evolution (2mks)
Reason - Suggest the significance of the above named type of evolution for the organism (1mk)
- Suggest the type of evolution that is exemplified by the organisms labeled D, E and F. Give reason for your answer
-
- Explain briefly the meaning of analogous structures (1mk)
- Give one example of analogous structure (1mk)
-
MARKING SCHEME.
-
-
Food
Procedure
Observation
Conclusion
Starch
put two millilitres of suspension M into a clean test tube. Add two drops of iodine solution and shake well.
Brown colour of iodine SOLUTION turns blue-black
starch present;
Reducing sugar
put two millilitres of suspension M into a clean test tube. Add of two millilitres Benedict’s solution, shake well and heat to boil
Rej If Benedict’s is not in possessive form
The blue colour of Benedict’s solution remains
Rej: no colour change
Reducing sugars absent.
Protein
put two millilitres of suspension M into a clean test tube. Add two millilitres of sodium hydroxide solution and shake well.
Slowly add 2 drops of Copper (II) sulphate solution and shake well.
On adding Copper (II) sulphate solution, a blue ring forms on the solution. On shaking, the mixture turns purple
proteins present.
Vitamin C
put two millilitres of DCPIP solution into a clean test tube. Add solution M dropwise while shaking.
The blue colour of DCPIP solution persist.
Vitamin C absent.
- Amylase. Any two correct 2marks.
Maltase.
protease - Sodium hydrogen carbonate. To neutralise excess hydrochloric acid. 1mark.
Hydrochloric acid. To hydrolyse complex sugars (non-reducing sugars) to simple sugars (reducing sugars). 1 mark.
-
-
- (4 marks)
Illustration Name of mutation
I Non -disjunction
II Deletion.
III Inversion.
IV Translocation - Brings about reversing the gene sequence thus enhancing advantageous or disadvantageous genes (1 mark)
- lethal since the offspring may lose genes responsible for the synthesis of some vital proteins (2 marks)
- During prophase (1 mark)
-
- Random and spontaneous change in individual’s genetic makeup. (1 mark)
- Very high temperatures.
Radiations: alpha, gamma, beta, UV and X-rays
Viruses: papilloma
Heavy metals: mercury.
Any two correct answers (2marks)
- (4 marks)
-
-
-
specimen
Food
reason
A
Aquatic matter and Invertebrates
Wide shovel shaped beak
B
Nectar
Long, thin beak
C
Nuts
Short, thick strong beak
F
Flesh
Strong sharp curved talons
-
part
Habitat
Reason
D
Aquatic
Webbed feet for swimming / wading
E
Tree branches
Long fingers / toes for perching
-
-
- Divergent evolution
Reason: similar basic structure and embryonic origin but modified into different forms / appearances (2mks) - Enable the organisms / animals to utilize different ecological niches, to avoid competition for food. (1mrk)
- Divergent evolution
-
- Structures with different embryonic origin but have similar function
-
- Wings of birds and insects. (1mrk)
- Eye of mammals and octopus. (mark one)
-
CONFIDENTIAL
- Each candidate should be supplied with the following
- 3 test tubes in test tube rack.
- Iodine solution – supplied with a dropper
- Adequate distilled water
- Benedicts solution– supplied with a dropper
- Means of heating
- 10% Sodium Hydroxide– supplied with a dropper
- 1% Copper (II) Sulphate– supplied with a dropper
- DCPIP– supplied with a dropper
- 12cm3 of solution M in a boiling tube labeled as solution M
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